Q.by@Anthology Yawwwwwww.... Question from @antarapayoga

BCole

Jawab:

x = -11/2

Penjelasan dengan langkah-langkah:

akar dari akar 3^2x+2 x 9^3/2 = akar 27^1/2

akar 3^x+1 x (3^2)^3/2 = (27^1/2)^1/2

akar 3^x+1 x 3^3 = 27^1/4

akar 3^x+1 x 27 = akar^4 dari 27

27 akar 3^x+1 = akar^4 dari 27

akar 3^x+1 = akar^4 dari 27 : 27

3^x+1/2 = 3^-9/4

(x+1)/2 = -9/4

4(x+1) = -18

4x+4 = -18

4x = -22

x = -11/2

1 votes Thanks 1

azrella

$\rm \sqrt{ \sqrt{ {3}^{2x + 2}} } \cdot {9}^{ \frac{3}{2} } = \sqrt{ {27}^{ \frac{1}{2} } }$

$\rm \sqrt{ \sqrt{ {3}^{2x + 2}} } \cdot {9}^{ \frac{3}{2} } = {27}^{ \frac{1}{4} }$

$\rm (\sqrt{ \sqrt{ {3}^{2x + 2}} } \cdot {9}^{ \frac{3}{2} } {)}^{4} = ( {27}^{ \frac{1}{4} } {)}^{4}$

$\rm {3}^{2x + 2} \cdot {9}^{6} = 27$

$\rm {3}^{2x + 2} \cdot {(3}^{2} {)}^{6} = {3}^{3}$

$\rm {3}^{2x + 2} \cdot {3}^{12} = {3}^{3}$

$\rm {3}^{2x + 2} \cdot {3}^{12 - 3} = {3}^{3 - 3}$

$\rm {3}^{2x + 2} \cdot {3}^{9} = {3}^{0}$

$\rm {3}^{2x + 2 + 9} = {3}^{0}$

$\rm {3}^{2x + 11} = {3}^{0}$

$\rm2x + 11 = 0$

$\rm2x = - 11$

$\rm \: x = - \frac{11}{2}$

1 votes Thanks 1