Question

Q.50+
1.tentukan nilai limit fungsi aljabar berikut :
Lim ( x² + 8x - 10x + 26 )
x => 2

2.tentukan nilai 2x+4y dari persamaan linear dua variabel berikut ini !
a.4x + 3y = 25
b.2x + y = 11

dah cuma 2 doank!
yok semangat pengkuli poin!​

Answer 1

Materi : Limit Fungsi dan SPLDV

Soal Nomor 1

Lim ( x => 2 ) = [ x = 2 ]

\________________/

x² + 8x - 10x + 26

= ( x² - 2x + 26 )

= (2)² - 2(2) + 26

= 4 - 4 + 26

= 0 + 26

= { 26 }

Soal Nomor 2

4x + 3y = 25

2x + y = 11 [ y = 11 - 2x ]

\____/ [ Metode Substitusi ( y => x ) ]

4x + 3( 11 - 2x ) = 25

4x + 33 - 6x = 25

6x - 4x = 33 - 25

2x = 8

x = 8/2

[ x = 4 ]

()()()()()()()

2x + y = 11

2(4) + y = 11

y + 8 = 11

y = 11 - 8

[ y = 3 ]

Hasil / Result :

{ x = 4 dan y = 3 }

Semoga bisa membantu

Answer 2

بِسْـــمِ اللَّهِ الرَّحْمَــنِ الرَّحِيْمِ

...

Nomor 1:

Nomor 2:

4x + 3y = 25 .... |×1| 4x + 3y = 25 ... (1)

2x + y = 11 ........ |×3| 6x + 3y = 33 .... (2)

• Eliminasi y dari persamaan (1) & (2)

4x + 3y = 25

6x + 3y = 33

__________ –

-2x = -8

x = -8 ÷ (-2)

x = 4

• Substitusi x = 4 ke pers (2)

2x + y = 11

2(4) + y = 11

8 + y = 11

8 - 11 = - y

-3 = -y

3 = y

• Nilai 2x + 4y

2(4) + 4(3)

= 8 + 12

= 20

...

وَاللَّهُ عَالَمُ بِاالصَّوَافَ