1.) 100^8 × 100^5 ÷ 100^3 × 100^8 ÷ 100^5 × 100^3 ÷ 100^5 2.) jika 2a + 8 = 24, 2b - 3 + 5 = 8, 2c + 7 - 3 = 14. Maka tentukan nilai dari : A = a × b + c - a × b - c ÷ c B = a × b × c + c - b + a - c 3.) diketahui sebuah bangun ruang balok mempunyai panjang 8 cm, lebar 3 cm, dan tinggi 5 cm. Carilah Volume dan Luas permukaan bangun balok trsbt __________ Clue : No 1 disederhanakan saja
Jawaban:
1). Materi tentang eksponen (Bilangan Berpangkat)
= 100⁸ x 100⁵ : 100³ x 100⁸ : 100⁵ x 100³ : 100⁵
Ingat;
Maka:
atau
2). Materi tentang Aljabar ( SPLSV ) { sistem persamaan linear satu variabel}.
Jika 2a + 8 = 24, 2b - 3 + 5 = 8, dan 2c + 7 - 3 = 14
2a + 8 = 24
2a = 24 - 8
2a = 16
a = 16:2 ≈ 8
2b - 3 + 5 = 8
2b + 2 = 8
2b = 8-2
2b = 6
b = 6:2 ≈ 3
2c + 7 - 3 = 14
2c + 4 = 14
2c = 14-4
2c = 10
c = 10:2 ≈ 5
Maka, nilai dari:
A = a x b + c - a x b - c : c
A = (8 x 3) + 5 - (8 x 3) - (5 : 5)
A = 24 + 5 - 24 - 1
A = 4
B = a x b x c + c - b + a - c
B = (8 x 3 x 5) + 5 - 3 + 8 - 5
B = 120 + 2 + 3
B = 125
3). Materi tentang bangun ruang balok
Ukuran balok ; Panjang 8 cm, lebar 3 cm, dan tinggi 5 cm.
V = panjang x lebar x tinggi
V = 8 cm x 3 cm x 5 cm
V = 24 cm² x 5 cm
V = 120 cm³
L = 2 (pl + pt + lt)
L = 2 ((8cm x 3cm) + (8cm x 5cm) + (3cm x 5cm))
L = 2 (24 cm² + 40 cm² + 15 cm²)
L = 2 (79 cm²)
L = 158 cm²
SOAL 1
100⁸ × 100⁵ ÷ 100³ × 100⁸ ÷ 100⁵ × 100³ ÷ 100⁵
= 100⁸ + ⁵ - ³ + ⁸ - ⁵ + ³ - ⁵
= 100¹³ - ³ + ⁸ - ⁵ + ³ - ⁵
= 100¹⁰ + ⁸ - ⁵ + ³ - ⁵
= 100¹⁸ - ⁵ + ³ - ⁵
= 100¹³ + ³ - ⁵
= 100¹⁶ - ⁵
= 100¹¹
= (10²)¹¹
= 10²²
SOAL 2
Nilai a
2a + 8 = 24
2a = 24 - 8
2a = 16
a = 16 ÷ 2
a = 8
Nilai b
2b - 3 + 5 = 8
2b + 2 = 8
2b = 8 - 2
2b = 6
b = 6 ÷ 2
b = 3
Nilai c
2c + 7 - 3 = 14
2c + 4 = 14
2c = 14 - 4
2c = 10
c = 10 ÷ 2
c = 5
A = a × b + c - a × b - c ÷ c
A = 8 × 3 + 5 - 8 × 3 - 5 ÷ 5
A = (8 x 3) + 5 - (8 x 3) - (5 : 5)
A = 24 + 5 - 24 - 1
A = 24 + 5 - 25
A = 24 - 20
A = 4
B = a × b × c + c - b + a - c
B = 8 × 3 × 5 + 5 - 3 + 8 - 5
B = (8 x 3 x 5) + 5 - 3 + 8 - 5
B = (24 × 5) + 5 - 3 + 8 - 5
B = 120 + 5 - 3 + 3
B = 120 + 5
B = 125
SOAL 3
V Balok = P × L × T
V Balok = 8 x 3 x 5
V Balok = 8 x 15
V Balok = 120 cm³
Lp Balok = 2 × (PL + PT + LT)
Lp Balok = 2 × [(8 × 3) + (8 × 5) + (3 × 5)]
Lp Balok = 2 × [24 + 40 + 15]
Lp Balok = 2 × [24 + 55]
Lp Balok = 2 × 79
Lp Balok = 158 cm²
UwU