Question

• Q. • Math... ~



Soal Terlampir di atas !
Cuman 2 Soal...



No Ngasal ❌
No Bahasa Alien ❌
No Copy ❌​

Answer 1

Jawab:

Luas Δ = 1/2 × alas × tinggi

2.

a. Luas ΔABC

Luas ΔABC = Luas ΔBCD - Luas ΔACD

                   = (1/2 × (AD + AB) × CD) - (1/2 × AD ×CD)

                   = (1/2 × 15 cm × 8 cm) - (1/2 × 6 cm × 8 cm)

                   = 60 cm² - 24 cm²

                   = 36 cm²

b. keliling ΔABC

Keliling ΔABC = AB + BC + AC

Mencari AC dengan rumus phytagoras (Karena ΔACD siku-siku)

AC² = AD² + CD²

AC² = (6 cm)² + (8 cm)²

AC² = 36 cm² + 64 cm² = 100 cm²

AC = 10 cm

Keliling ΔABC = AB + BC + AC

                       = 9 cm + 17 cm + 10 cm

                       = 36 cm

3.

Luas ΔABC = 84 cm

AB = 13 cm

BC = 14 cm

AC = 12 cm

a. Keliling ΔABC

Keliling ΔABC = AB + BC + AC

                        = 13 cm + 14 cm + 12 cm

                        = 39 cm

b. Panjang AD + BE

Luas ΔABC = 1/2 × AC ×BE = 1/2 ×BC × AD

- Luas ΔABC = 1/2 × AC ×BE

84 cm² = 1/2 × 12 cm × BE

BE = 14 cm

- Luas ΔABC = 1/2 ×BC × AD

84 cm² = 1/2 × 14 cm × AD

AD = 12 cm

AD + BE = 12 cm + 14 cm = 16 cm