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Gunakan teorema sisaP(x) habis dibagi x-4
P(4)=4a+b=0
b=-4a ...(1)
P(x) dibagi x+3 sisa 14
P(-3)=-3a+b=14 (2)
P(x) dibagi x²-x-12
P(x)=(x²-x-12)h(x)+ax+b
P(x)=(x-4)(x+3)h(x)+ax+b
P(4)=4a+b=0
P(-3)=-3a+b =14
Substitusi (1) ke (2)
-3a-4a=14
-7a=14
a=-2
b=-4a
b=8
Jadi, sisa P(x) dibagi x²-x-12 adalah
-2x+8
Cara dan jawaban ada di lampiran