Odpowiedź:
Niech A = ( - 3, 5) C = ( 3, 1 )
oraz B = ( - 3, - 2)
więc
-->
BA = [ - 3 - ( - 3), 5 - ( - 2 ) ] = [ 0 , 7 ]
zatem D = C + BA = ( 3, 1 ) + [ 0, 7 ] = ( 3 + 0, 1 + 7 ) = ( 3 , 8 )
=========================================================
II sposób :
BC = [ 3 - ( - 3), 1 - ( - 2) ] = [ 6 , 3 ]
D = A + BC = ( -3, 5 ) + [ 6, 3 ] = (- 3 + 6, 5 + 3 ) = ( 3, 8 )
===================================================
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Odpowiedź:
Niech A = ( - 3, 5) C = ( 3, 1 )
oraz B = ( - 3, - 2)
więc
-->
BA = [ - 3 - ( - 3), 5 - ( - 2 ) ] = [ 0 , 7 ]
-->
zatem D = C + BA = ( 3, 1 ) + [ 0, 7 ] = ( 3 + 0, 1 + 7 ) = ( 3 , 8 )
=========================================================
II sposób :
-->
BC = [ 3 - ( - 3), 1 - ( - 2) ] = [ 6 , 3 ]
więc
-->
D = A + BC = ( -3, 5 ) + [ 6, 3 ] = (- 3 + 6, 5 + 3 ) = ( 3, 8 )
===================================================
Szczegółowe wyjaśnienie: