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Lo que les corresponde: x
200=nx 200=(n-5)(x+20)
nx=(n-5)(x+20)
nx=nx+20n-5x-100 (Tachamos nx)
0=20n-5x-100
(Multiplicamos "n" por 0)
0=20n²-100n-100
0=20(n²-5n-50) (Multiplicamos "20" por 0)
0=n²-5n-50
n -10....n=10
n 5.....n=-5
n=10