Jawab:114
Penjelasan:Cari hasil dari √196 dulu!√196 √1 = 1, digit awal = 1... 1 (cari bilangan kuadrat yg akhirannya 6,....↓ lalu diakarin utk menghasilkan digit akhir yg mungkin)-------- - √16 = 4 √36 = 6.... 0 < >.... 0 < 1, maka digit akhir = 4= 1 4---------------------------------maka,√196 + 10² =14 + 10² =14 × (1+(10²/14)) =14 × (1+ ¹⁰⁰/₁₄) =14 × (1+ (¹⁰⁰ : ²)/(₁₄ : ₂)) =14 × (1 + ⁵⁰/₇) =14 × (⁷/₇+⁵⁰/₇) =14 × ( ⁵⁷/₇ ) =¹⁴/₇ × 572 × 57 =114
( xcvi )
Jawaban:
√196 + 10²
= √14² + ( 10 × 10 )
= 14 + 100
= 114
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Jawab:
114
Penjelasan:
Cari hasil dari √196 dulu!
√196 √1 = 1, digit awal = 1
... 1 (cari bilangan kuadrat yg akhirannya 6,
....↓ lalu diakarin utk menghasilkan digit akhir yg mungkin)
-------- - √16 = 4 √36 = 6
.... 0 < >
.... 0 < 1, maka digit akhir = 4
= 1 4
---------------------------------
maka,
√196 + 10² =
14 + 10² =
14 × (1+(10²/14)) =
14 × (1+ ¹⁰⁰/₁₄) =
14 × (1+ (¹⁰⁰ : ²)/(₁₄ : ₂)) =
14 × (1 + ⁵⁰/₇) =
14 × (⁷/₇+⁵⁰/₇) =
14 × ( ⁵⁷/₇ ) =
¹⁴/₇ × 57
2 × 57 =
114
( xcvi )
Jawaban:
√196 + 10²
= √14² + ( 10 × 10 )
= 14 + 100
= 114