przyprostokątne trójkąta prostokątnego maja dlugosci 5cm i 12 cm. oblicz dlugosc przeciwprostkątnej i wartosci funkcji trygonometrycznych obu katów ostrych trójkąta
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c^2=a^2+b^2
a=5; b=12
c^2=5^2+12^2=25+144=169
c=sqrt169=13
sin aIfa=a/c=5/13 sin beta=b/c=12/13
cos aIfa=b/c=12/13 cos beta=a/c=5/13
tg alfa=a/b=5/12 tg beta=b/a=12/5=2 2/5
ctg aIfa=b/a=12/5=2 2/5 ctg beta=a/b=5/12
a = 5 cm
b = 12 cm
c = ?
Z tw. Pitagorasa:
a²+b² = c²
c² = 5²+12² = 25+144 = 169
c = √169 cm
c = 13 cm
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sin α = a/c = 5/13
cos α = b/c = 12/13
tg α = a/b = 5/12
ctg α = b/a = 12/5
sin β = b/c = 12/13
cos β = a/c = 5/13
tg β = b/a = 12/5
ctg β = a/b = 5/12