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a=√2
b=3√2
przeciwprostokatna =c
z pitagorasa
(√2)+(3√2)²=c²
2+18=c²
c=√20=2√5
obwod Δ
O=a+b+c=√2+3√2=2√5=4√2+2√5=2(2√2+√5)