Question

Przyjrzyj się, jak Asia i Leszek rozwiązywali to samo równanie.

Asia S.
3(2x-1) = 12 |:3
2x-1 = 4 |+1
2x = 5 |:2
x = ⁵₂
x = 2½

Leszek J.
3(2x-1)=12
6x-3-12 |+3
6x=15 |:6
x= ¹⁵₆
x=2½

Rozwiąz podane równania:
a) sposobem Asi:
2(5x - 1) = 8

½(4y + 6) = 3

-3(x - 2) = -9


a) sposobem Leszka:
2(5x - 1) = 8

½(4y + 6) = 3

-3(x - 2) = -9


z góry dzieki. ; D

Answer 1

Sposobem asi
a)2(5x-1)=8 /:2
5x-1=4 /+1
5x=5 /:5
x=1
b)1\2(4y+6)=3 /*2
4y+6=6 /-6
4y=0
y=0
c)-3(x-2)=-9 /:(-3)
x-2=3 /+2
x=5

sosobem leszka
a)2(5x-1)=8
10x-2=8 /+2
10x=10 /:10
x=1
b)1\2(4y+6)=3
2y+3=3 /-3
2y=0
y=o
c)-3(x-2)=-9
-3x+6=-9 /-6
-3x=-15 /:(-3)
x=5

Answer 2

A) sposobem Asi:
2(5x - 1) = 8 |:2
5x-1 = 4 |+1
5x = 5 |:5
x = 1

½(4y + 6) = 3 |:1/2
4y+6 = 6 |-6
4y = 0 |:4
y = 0

-3(x - 2) = -9 |:(-3)
x-2 = 3 |+2
x = 5


a) sposobem Leszka:
2(5x - 1) = 8
10x-2 = 8 |+2
10x = 10 |:10
x = 1

½(4y + 6) = 3
2y+3 = 3 |-3
2y = 0 |:2
y = 0

-3(x - 2) = -9
-3x+6 = -9 |-6
-3x = -15 |:(-3)
x = 5

Answer 3

Rozwiąz podane równania:
a) sposobem Asi:
2(5x - 1) = 8 | :2
5x-1=4 |+1
5x=5
x=1


½(4y + 6) = 3 | : ½
4y+6=6 | -6
4y=0
y=0

-3(x - 2) = -9 | :-3
x-2=3 | +2
x=5


a) sposobem Leszka:
2(5x - 1) = 8
10x-2=8
10x=10
x=1

½(4y + 6) = 3
2y+3=3
2y=0
y=0

-3(x - 2) = -9
-3x+6=-9
-3x=-15
x=5