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połówki przekatnych tworzą z bokiem trójkąt prostokątny
a=7½cm:2=3,75cm
b=18cm:2=9cm
c= bok rombu
c²=3,75²+9²
c²=14,0625+81
c²=95,0625
c=9,75cm
bok rombu ma 9,75cm
18/2=9
9²+3,75²=bok rombu²
bok rombu²=81+14,0625
bok rombu²=95,0625
bok rombu=√95,0625
bok rombu=9,75