Przekrój osiowy walca jest kwadratem o POlu 8 cm kwadratowych, oblicz pole i objętość tego walca.
Dane :
P = 8 cm²
P= a²
8 = a²
a = √8
a = √4*2
a = 2√2 cm
h = 2√2 cm
d = a= 2√2
r = 2√2/2 = √2 cm
Pc= 2πr (r+h)
Pc = 2 π √2 (√2 + 2√2)
Pc = 2 π √2 * 3√2 = 12 π cm²
V = π r² h
V = π (√2)² * 2√2 = 4√2 π cm³
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Dane :
P = 8 cm²
P= a²
8 = a²
a = √8
a = √4*2
a = 2√2 cm
h = 2√2 cm
d = a= 2√2
r = 2√2/2 = √2 cm
Pc= 2πr (r+h)
Pc = 2 π √2 (√2 + 2√2)
Pc = 2 π √2 * 3√2 = 12 π cm²
V = π r² h
V = π (√2)² * 2√2 = 4√2 π cm³