Przedstaw w prostszej postaci:
a) (cosαtgα)²-(sinαctgα)²=
Ma wyjść: sin²α-cos²α=
b) sinαcosα(tgα+ctgα)
Ma wyjść: 1
c)sinα(sinα+ctgαcosα)=
ma wyjść: 1
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(cosαtgα)²-(sinαctgα)²=cos²a*tg²a-sin²a*ctg²a=sin²α-cos²α=-cos2a.
sinαcosα(tgα+ctgα)=(sina*cosa*sina)/cosa + (sina*cosa*cosa)/sina= sin²a+cos²a=1
sinα(sinα+ctgαcosα)=sin²a+sina*cosa*cosa/sina=sin²a+cos²a=1