Przedstaw liczbę;√72+3√32-5√18w postaci a√b.
V72 + 3V32 - 5V18 =
V(36*2) + 3 V(16*2) - 5V(9*2) =
6V2 + 3*4V2 - 5*3V2 =
6V2 + 12V2 - 15V2 =
(6+12-15) V2 = 3V2
mam nadzieje ze pomoglam
pozdrawiam i licze na naj :)
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V72 + 3V32 - 5V18 =
V(36*2) + 3 V(16*2) - 5V(9*2) =
6V2 + 3*4V2 - 5*3V2 =
6V2 + 12V2 - 15V2 =
(6+12-15) V2 = 3V2
mam nadzieje ze pomoglam
pozdrawiam i licze na naj :)