przedstaw funkcje f(x)= -2x^2-6x+2 w postaci kanonicznej.
f(x) = -2x² - 6x + 2
Postać kanoniczna : y=a(x-p)²+q
p=-b/2a = 6/-4=-1½
q=-Δ/4a
Δ=(-6)²-4*(-2)*2=36+16=52
q=-52/-8=6½
y=-2(x+1½)²+6½
p=-b/2a
a=-2
p=6/(-4)=-1,5
Δ=36+16=52
q=-52/(-8)=6,5
f(x)=a(x-p)²+q
f(x)=-2(x+1,5)²+6,5
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f(x) = -2x² - 6x + 2
Postać kanoniczna : y=a(x-p)²+q
p=-b/2a = 6/-4=-1½
q=-Δ/4a
Δ=(-6)²-4*(-2)*2=36+16=52
q=-52/-8=6½
y=-2(x+1½)²+6½
p=-b/2a
q=-Δ/4a
a=-2
p=6/(-4)=-1,5
Δ=36+16=52
q=-52/(-8)=6,5
f(x)=a(x-p)²+q
f(x)=-2(x+1,5)²+6,5