prosze z opisem !!!!
zad.3k= log3 0,1 + log3 90 / 22k= log3 0,1 + log3 90 log3(0,1*90) <-- na to jest wzór :)2k=log3 9 ---> 3^x=9 x=22k = 2k=1zad. 4liczysz delte x^2 + 10x +16=0d= 100-64=36pierwiastek 6 x1= -10+6/2=-2 x2=-10-6/2= -8y=a(x-p)+q=(x+2)-8 :)
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zad.3
k= log3 0,1 + log3 90 / 2
2k= log3 0,1 + log3 90 log3(0,1*90) <-- na to jest wzór :)
2k=log3 9 ---> 3^x=9 x=2
2k = 2
k=1
zad. 4
liczysz delte x^2 + 10x +16=0
d= 100-64=36
pierwiastek 6 x1= -10+6/2=-2 x2=-10-6/2= -8
y=a(x-p)+q=(x+2)-8 :)