October 2018 1 17 Report

Prosze szybko o rozwiazanie plisss

3s+2(a^3-s^2+a)-(2a^3-2s^2)=
8(ó+3ł^2)+3(2ł-8ł^2)-3ó=
a^2(a-l)-a^3+8(a^2+a)-7a^2=
3(k+l)-(-5k)-4k-3=
7w^2-6w^2-(w^2-4s)-(s^2-w)+s^2=
5n+o(o^2-l)+4(o-o^3)+3o^3=
4(y+y^2)-6y^2+2(y^2+y+l)-2=
\2(k+k^2)-2k^2-2(k+3)+6=
6i+2(4i^2+i)-i^2-(7i^2+6i)=
7(-b^2+2a-b)-(9a-8b)+7b^2=
6(n+n^2)-(3-n^2)-7n^2+3=
5(o+2)+3(-2-o)-4=
2(c+3)-5-(c^2-c+l)+c^2=
5(i+k+2)-(3+5k+i)-7=


Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.