Prosze o rozwiązanie
a)(x-2)²=x²
x²-4x+4=x²
-4x+4=0
-4x=-4
x=1
b)(2x-2)²=4x(x-4)
4x²-8x+4=4x²-16x
-8x+4=-16x
8x+4=0
8x=-4
x=-½
c)x(4x-3)=(2x-3)²
4x²-3x=4x²-12x+9
-3x=-12x+9
9x=9
d)x(0,04x-1,3)=(0,2x-1)²
0,04x²-1,3x=0,04x²-0,4x+1
-1,3x=-0,4x+1
-0,9x=1
x=-1¹/₉
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a)(x-2)²=x²
x²-4x+4=x²
-4x+4=0
-4x=-4
x=1
b)(2x-2)²=4x(x-4)
4x²-8x+4=4x²-16x
-8x+4=-16x
8x+4=0
8x=-4
x=-½
c)x(4x-3)=(2x-3)²
4x²-3x=4x²-12x+9
-3x=-12x+9
9x=9
x=1
d)x(0,04x-1,3)=(0,2x-1)²
0,04x²-1,3x=0,04x²-0,4x+1
-1,3x=-0,4x+1
-0,9x=1
x=-1¹/₉