Prosze o rozwiązanie układu równań:
36=(v+6)(t-1)
36= vt
odp. w załączniku
36=[v+6][t-1]
36=vt
36/t=v
36=[36/t+6][t-1]
36=36/t*t-36/t*1+6t-6
36=36-36/t+6t-6 /*t
36t=36t-36+6t^2-6t
36t-36t+6t-6t^2=36
-6t^2+6t-36=0 /-6
t^2-t+6=0
delta=-1^2-4*1*6=1+24=25
pierw z delta=5
t1=1-5/2=-4/2=-2
t2=1+5/2=6/2=3
czyli
t1=-2
t2=3
v=36/t
v1=36/t1=36/-2=-18
v2=36/t2=36/3=12
odp
t1=-2 t2=3
v1=-18 i v2=12
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odp. w załączniku
36=[v+6][t-1]
36=vt
36/t=v
36=[36/t+6][t-1]
36=36/t*t-36/t*1+6t-6
36=36-36/t+6t-6 /*t
36t=36t-36+6t^2-6t
36t-36t+6t-6t^2=36
-6t^2+6t-36=0 /-6
t^2-t+6=0
delta=-1^2-4*1*6=1+24=25
pierw z delta=5
t1=1-5/2=-4/2=-2
t2=1+5/2=6/2=3
czyli
t1=-2
t2=3
v=36/t
v1=36/t1=36/-2=-18
v2=36/t2=36/3=12
odp
t1=-2 t2=3
v1=-18 i v2=12