prosze o rozwiązanie tych 2 zadan co są w załączniku
14.
a). (x+2)(x-2)-2x>x²+8
x²-4-2x>x²+8
x²-2x-x²>8+4
-2x>12 |:(-2)
x<-6
b). 3x²-3(1-x)²-6 < -3x
3x²-3(1-2x+x²)-6<-3x
3x²-3+6x-3x²-6 <-3x
3x²+6x-3x²+3x<3+6
9x<9 |:9
x<1
c). (y+ 1/2 )² >= y(y- 3/4)
y²+y+ 1/4 >= y²-3/4y
y²+y-y²+3/4 y >= -1/4
1 i 3/4y >= -1/4
7/4 y>= -1/4 |*4/7
y>= - 1/7
d). 4(x+1)(x-3) < (2x-3)²
4(x²-3x+x-3) < 4x²-12x+9
4(x²+4x-3) < 4x²-12x+9
4x²+16x-12 < 4x²-12x+9
4x²+16x-4x²+12x < 9+12
28x < 21 |:28
x< 3/4
e). (x+3)² > x(x+6)
x²+6x+9 > x²+6x
x²+6x-x²-6x > -9
0>-9 (sprzeczne)
f). 4y-3/6 +3 <= 3y/2 + 5/8 |*24
16y-12+72 <= 36y+15
16y-36y <= 15+12-72
-20y <= -45 |:(-20)
y >= 2,25
g). 2x+5/6 - x-4/3 <1 |*6
2x+5-2x-8 <6
2x-2x < 6-5+8
0< 9
(sprzecznosc)
h). (1+x)³ -x(x²-2) >= 1+3x²
1+3x+3x²+x³ -x³-2x >= 1+3x²
3x+3x²+x³-x³-2x-3x² >= 1-1
x >= 0
i). 1,5x+15 < 29-1,3x
1,5x+1,3x < 29-15
2,8x < 14 |:2,8
x < 5
j). 2(x-1)+3 <= 4(x+3)-1
2x-2+3 <= 4x+12-1
2x-4x <= 12-1+2-3
-2x <= 10 |:(-2)
x>= -5
k). 1+ y/4 -y <-3 |*4
4+y-4y<-12
-3y<-12-4
-3y<-16 |:(-3)
y> 16/3
l). 2z-1 < 1/2z +1 |*2
4z-2 < z+2
4z-z < 2+2
3z<4
z< 3/4
15. (x-1)(x+1)+x <x² - 2 i 1/2
x²-1+x < x²- 2,5
x < -1,5
odp: -3, -5
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14.
a). (x+2)(x-2)-2x>x²+8
x²-4-2x>x²+8
x²-2x-x²>8+4
-2x>12 |:(-2)
x<-6
b). 3x²-3(1-x)²-6 < -3x
3x²-3(1-2x+x²)-6<-3x
3x²-3+6x-3x²-6 <-3x
3x²+6x-3x²+3x<3+6
9x<9 |:9
x<1
c). (y+ 1/2 )² >= y(y- 3/4)
y²+y+ 1/4 >= y²-3/4y
y²+y-y²+3/4 y >= -1/4
1 i 3/4y >= -1/4
7/4 y>= -1/4 |*4/7
y>= - 1/7
d). 4(x+1)(x-3) < (2x-3)²
4(x²-3x+x-3) < 4x²-12x+9
4(x²+4x-3) < 4x²-12x+9
4x²+16x-12 < 4x²-12x+9
4x²+16x-4x²+12x < 9+12
28x < 21 |:28
x< 3/4
e). (x+3)² > x(x+6)
x²+6x+9 > x²+6x
x²+6x-x²-6x > -9
0>-9 (sprzeczne)
f). 4y-3/6 +3 <= 3y/2 + 5/8 |*24
16y-12+72 <= 36y+15
16y-36y <= 15+12-72
-20y <= -45 |:(-20)
y >= 2,25
g). 2x+5/6 - x-4/3 <1 |*6
2x+5-2x-8 <6
2x-2x < 6-5+8
0< 9
(sprzecznosc)
h). (1+x)³ -x(x²-2) >= 1+3x²
1+3x+3x²+x³ -x³-2x >= 1+3x²
3x+3x²+x³-x³-2x-3x² >= 1-1
x >= 0
i). 1,5x+15 < 29-1,3x
1,5x+1,3x < 29-15
2,8x < 14 |:2,8
x < 5
j). 2(x-1)+3 <= 4(x+3)-1
2x-2+3 <= 4x+12-1
2x-4x <= 12-1+2-3
-2x <= 10 |:(-2)
x>= -5
k). 1+ y/4 -y <-3 |*4
4+y-4y<-12
-3y<-12-4
-3y<-16 |:(-3)
y> 16/3
l). 2z-1 < 1/2z +1 |*2
4z-2 < z+2
4z-z < 2+2
3z<4
z< 3/4
15. (x-1)(x+1)+x <x² - 2 i 1/2
x²-1+x < x²- 2,5
x < -1,5
odp: -3, -5