prosze o rozwiazanie zadan matematy nowy kaledarz gimnazjalisty cwiczenia kontrolne s 48 A,B
zad A
[2] - znaczy to ze do potegi 2
a) 5x[2]-2x-4x[2]+5-x[2]+x
b) 5(4a-3b)-6(5-3a+2b)
c) (2-a)(3a+4)-8
d) (6-3x)(4x-6)-8
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a) 5x[2]-2x-4x[2]+5-x[2]+x = 5x[2]-4x[2]-x[2]-2x+x+5 = -x+5
b) 5(4a-3b)-6(5-3a+2b) = 20a-15b-30+18a-12b = 38a-27b-30
c) (2-a)(3a+4)-8 = 6a+8-3a[2]-4a-8 = -3a[2]+2a
d) (6-3x)(4x-6)-8 = 24x-36-12x[2]+18x-8 = -12x[2]+42x-44
a)
5x²-2x-4x²+5-x²+x = -x+5 = 5-x
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b)
5(4a-3b)-6(5-3a+2b) = 20a-15b-30+18a-12b = 38a-27b-30
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c)
(2-a)(3a+4)-8 = 6a+8-3a²-4a-8 = 2a-3a²= a(2-3a)
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d)
(6-3x)(4x-6)-8 = 24x-36-12x²+18x-8 = 42x-44-12x²=2(21x-22-6x²)