Prosze o rozwiazanie tych 3 zadan,dam najjjj...Potrzebuje to na dzisiaj....
1]
√2½×√⅝-∛1,8:∛8⅓=
√[⁵/₂×⅝]-∛[⁹/₅:²⁵/₃]=
√²⁵/₁₆-∛²⁷/₁₂₅=⁵/₄-³/₅=¹³/₂₀
2]
∛2×∛⁴/₂₇-√3,5:√1¹/₇=
∛⁸/₂₇-√⁷/₂:⁸/₇=
⅔-√⁴⁹/₁₆=⅔-⁷/₄=-1¹/₁₂
3]
a=2√48
b=√75
pole=ab=2√48×√75=2√3600=2×60=120j.²
obwód=2a+2b=2×2√48+2×√75=4√48+2√75=16√3+10√3=26√3
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1]
√2½×√⅝-∛1,8:∛8⅓=
√[⁵/₂×⅝]-∛[⁹/₅:²⁵/₃]=
√²⁵/₁₆-∛²⁷/₁₂₅=⁵/₄-³/₅=¹³/₂₀
2]
∛2×∛⁴/₂₇-√3,5:√1¹/₇=
∛⁸/₂₇-√⁷/₂:⁸/₇=
⅔-√⁴⁹/₁₆=⅔-⁷/₄=-1¹/₁₂
3]
a=2√48
b=√75
pole=ab=2√48×√75=2√3600=2×60=120j.²
obwód=2a+2b=2×2√48+2×√75=4√48+2√75=16√3+10√3=26√3