prosze o rozwiazanie caleczki w zalaczniku, bardzoo bardzo ladnie prosze
∫▒dx/√(x^2+4x+3)= ∫dx/〖〖(x〗^2+4x+3)〗^(1/2) =∫(〖x^2+4x+" " 3)〗^((-1)/2)=((〖x^2+4x+3)〗^(1/2))/(1/2)=2√(x^2+4x+3)
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∫▒dx/√(x^2+4x+3)= ∫dx/〖〖(x〗^2+4x+3)〗^(1/2) =∫(〖x^2+4x+" " 3)〗^((-1)/2)=((〖x^2+4x+3)〗^(1/2))/(1/2)=2√(x^2+4x+3)