Prosze o pomoc
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Podaj pierwiastki równania x(x+8)=10-(x-2)^2
x(x+8)=10-(x-2)^2
x^2+8x=10-x^-4x+4
x^2+8x+x^2+4x-14=0
2x^2+12x-14=0/:2
x^2+6x-7=0
delta=36+28
delta =64
pierwiastek z delty=8
x1=(-6-8)/2=-14/2=-7
x2=(-6+8)/2=2/2=1
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x(x+8)=10-(x-2)^2
x^2+8x=10-x^-4x+4
x^2+8x+x^2+4x-14=0
2x^2+12x-14=0/:2
x^2+6x-7=0
delta=36+28
delta =64
pierwiastek z delty=8
x1=(-6-8)/2=-14/2=-7
x2=(-6+8)/2=2/2=1