5. tgα = 2 + √3
tg(90° - α) = ctgα
ctgα = 1/tgα
ctgα = 1/(2 + √3) = (2 - √3)/[2 + √3)(2 - √3) = (2 - √3)/(4 - 3) =
= (2 - √3)/1 = 2 - √3
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5. tgα = 2 + √3
tg(90° - α) = ctgα
ctgα = 1/tgα
ctgα = 1/(2 + √3) = (2 - √3)/[2 + √3)(2 - √3) = (2 - √3)/(4 - 3) =
= (2 - √3)/1 = 2 - √3
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