Question

prosze o pomoc

5y=4+5(2y-3)-6(3y-4)

12x-11(4x-3)+10(8-5x)+8(8x-13)=0

3x-2[5(x-1)-4]=4(7-3x)

6[2-3(2x-5)]-5(1-2x)=7-2(11x-5)

plis potrzebuje za 15min

Answer 1

5y=4+5[2y-3]-6[3y-4]
5y=4+10y-15-18y+24
5y-10y+18y=4-15+24
13y=13    /:13
y=1

 

12x-11[4x-3]+10[8-5x]+8[8x-13]=0
12x-44x+33+80-50x+64x-104=0
12x-44x-50x+64x= -33-80+104
-18x= -9   /:[-18]
x=9/18
x=1/2

 

3x-2[5[x-1]-4]]=4[7-3x]
3x-2[5x-5-4]=28-12x
3x-2[5x-9]=28-12x
3x-10x+18=28-12x
3x-10x+12x=28-18
5x=10    /:5
x=2

 

6[2-3[2x-5]]-5[1-2x]=7-2[11x-5]
6[2-6x+15]-5+10x=7-22x+10
6[ -6x+17]-5+10x=7-22x+10
-36x+102-5+10x=7-22x+10
-36x+10x+22x=7+10-102+5
-4x= -80     /:[-4]
x=20