" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=3,14×3²=3,14×9=28,26cm²
b)
P=3,14×100=314cm²
2
L=2πr
L=6,28×2,5=15,7cm
L=6.28×2,1=13,188cm
P=Πr²
P≈3,14*3²
P=3,14*9
P≈28,26 cm²
b)o srednicy 20cm
r=10cm
P≈3,14*10²
P≈3,14*100
P≈314 cm²
2 podaj dlugosc okregu o srednicy:
a) 5cm
l=2Πr
l=10Π cm
b)4,2cm
l=8,4Π cm
1. P = π*r²
a) π * 3² = pi * 9 ≈ 28,26cm²
b) π * (0,5 * 20)² = π * 10² = π * 100 ≈ 314cm²
2. l = 2*π*r
a) l=2*π*5 ≈31,4
b) l=2*π*4,2 ≈26,376