Odpowiedź:
a)
[tex]|AB|=\sqrt{(3-3)^2+(8+2)^2} =10\\|AC|=\sqrt{(3+9)^2+(3+2)^2} =\sqrt{144+25} =13\\|BC|=\sqrt{(3+9)^2+(8-3)^2} =\sqrt{144+25} =13|[/tex]
b)
[tex]|AC|=13\\\\|AD|=\sqrt{(3+3)^2+(-6+2)^2} =\sqrt{36+16} =\sqrt{52} \\|DC|=\sqrt{(-9+3)^2+(3+6)^2} =\sqrt{36+81} =\sqrt{117} \\|AC|^2=|AD|^2+|DC|^2\\13^2=52+117\\169=52+117 \\[/tex]
Prawda
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Odpowiedź:
a)
[tex]|AB|=\sqrt{(3-3)^2+(8+2)^2} =10\\|AC|=\sqrt{(3+9)^2+(3+2)^2} =\sqrt{144+25} =13\\|BC|=\sqrt{(3+9)^2+(8-3)^2} =\sqrt{144+25} =13|[/tex]
b)
[tex]|AC|=13\\\\|AD|=\sqrt{(3+3)^2+(-6+2)^2} =\sqrt{36+16} =\sqrt{52} \\|DC|=\sqrt{(-9+3)^2+(3+6)^2} =\sqrt{36+81} =\sqrt{117} \\|AC|^2=|AD|^2+|DC|^2\\13^2=52+117\\169=52+117 \\[/tex]
Prawda