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Prosze o DOBRE rozwiazanie tych równań. Będzie naj ;)
Zad.1
x²-5x+6<0
Δ=1 x₁=3 x₂=2
(2,3)
zad.2
-2x²+3x+5>0
Δ=49 √Δ=7 x₁=-1 x₂=2,5
(-1;2,5)
zad.3
x²≤2
x²-2≤0
(x-√2)(x+√2)≤0
x=√2 x=-√2
<-√2,√2>
zad.4
x²+2x+2 ≤0
Δ=0 x₀=-2/2=-1
x∈{-1}
zad.5
4x>x²+4
x²+4-4x<0
Δ=0 x₀=4/2=2
x∈{2}
zad.6
x²-6x+8>0
Δ=4 √Δ=2 x₁=4 x₂=2
(∞,2)(4,∞)
zad.7
2x₂+5x-3<0
Δ=49 √Δ=7 x=½ x=-3
(-3,0)
zad.8
-3x²+8x-4≥0
Δ=16 √Δ=4 x=⅔ x=2
<⅔,2>
zad.9
9x²+16<0
roz. x∈R
Rozwiązanie:Dowolna liczba podniesiona do kwadratu jest dodatnia
zad.10
6x²-x-2≤0
Δ=49 √Δ=7 x=⅔ x=-½
<-½,⅔>
zad.11
4x²+2x+1≤0
Δ<0
zad.12
2x²+9x-5<0
Δ=121 √Δ=11 x=½ x=-5
(-5,½)
zad.13
5x²+2x-3>0
Δ=64 √Δ=8 x=0,6 x=-1
(∞,-1)(0,6;∞)
zad.14
x²-4x+4≥4
x²-4x≥0
x(x-4)≥0
x=0 x=4
(∞,0)(4,∞)
zad.15
x²+2x+1<9
x²+2x-8<0
Δ=36 √Δ=6 x=2 x=-4
(-4,2)
zad.16
(-√2,√2)
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Zad.1
x²-5x+6<0
Δ=1 x₁=3 x₂=2
(2,3)
zad.2
-2x²+3x+5>0
Δ=49 √Δ=7 x₁=-1 x₂=2,5
(-1;2,5)
zad.3
x²≤2
x²-2≤0
(x-√2)(x+√2)≤0
x=√2 x=-√2
<-√2,√2>
zad.4
x²+2x+2 ≤0
Δ=0 x₀=-2/2=-1
x∈{-1}
zad.5
4x>x²+4
x²+4-4x<0
Δ=0 x₀=4/2=2
x∈{2}
zad.6
x²-6x+8>0
Δ=4 √Δ=2 x₁=4 x₂=2
(∞,2)(4,∞)
zad.7
2x₂+5x-3<0
Δ=49 √Δ=7 x=½ x=-3
(-3,0)
zad.8
-3x²+8x-4≥0
Δ=16 √Δ=4 x=⅔ x=2
<⅔,2>
zad.9
9x²+16<0
roz. x∈R
Rozwiązanie:Dowolna liczba podniesiona do kwadratu jest dodatnia
zad.10
6x²-x-2≤0
Δ=49 √Δ=7 x=⅔ x=-½
<-½,⅔>
zad.11
4x²+2x+1≤0
Δ<0
zad.12
2x²+9x-5<0
Δ=121 √Δ=11 x=½ x=-5
(-5,½)
zad.13
5x²+2x-3>0
Δ=64 √Δ=8 x=0,6 x=-1
(∞,-1)(0,6;∞)
zad.14
x²-4x+4≥4
x²-4x≥0
x(x-4)≥0
x=0 x=4
(∞,0)(4,∞)
zad.15
x²+2x+1<9
x²+2x-8<0
Δ=36 √Δ=6 x=2 x=-4
(-4,2)
zad.16
x²≤2
x²-2≤0
(x-√2)(x+√2)≤0
x=√2 x=-√2
(-√2,√2)