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c = 5√2
a = ?
P = ?
Z tw. Pitagorasa:
a² + b² = c²
a² = c² - b²
a² = (5√2)² - (3√5)² = 50 - 45 = 5
Pk = a²
Pk = 5
x² +(3√5)²=(5√2)²
x²=50-45=5
x=√5 (bo x>0)
x jest też bokiem kwadratu, więc:
P=x²=(√5)²=5