Question

Proszę też o zalożenia

Answer 1

A)
x/(x³+27) * (x²+6x+9) = x*(x+3)² /(x+3)(x²-3x+9) = (x²+3x)/(x²-3x+9)
x∉{-3}
b)
(x²+2x+1)/(x²-2x+1) *(x-1)/(x+1) = (x+1)²/(x-1)² *(x-1)/(x+1) = (x+1)/(x-1)
x∉{-1,1}
c)
(x²+5x+6)/(x²-7x+12) * (x-4)/(x+3) = (x+2)(x+3)/(x-4)(x-3) * (x-4)/(x+3) = (x+2)/(x-3)
x∉{-3,3,4}