Proszę sprawdźcie mi to czy dobrze rozwiązałam: a) 4 (3a + 5) + 3 (5a - a) = 7+8a+3 b) 2(7p-3)-5(3p-1) = -3 c)-5(2-3m)-2m+8 = 3(2+4m)+8 d)2x(3x-4)+x(5-2x) = 5x-1 e)3u(2-4u)-5u(u+3) = 5u-1 f)-5t (2t-1)-2t(3-5t) = -10t-2
madzixxx696
Tak powinno być prawidłowo a) 4(3a+5)+3(5a-a)=12a+20+15a-3a=24a+20 b)2(7p-3)-5(3p-1)=14p-6-15p-1=-1p-7 c)-5(2-3m)-2m+8=-10+15m-2m+8=-2+13m d)2x(3x-4)+x(5-2x)=6x^2-8x+5x-2x^2=4x^2-3x e)3u(2-4u)-5u(u+3)=6u-12u^2-5u^2-15u=-9u-17u^2 f)-5t(2t-1)-2t(3-5t)=-10t^2+5t-6t+10t^2=-t
Mam nadzieję że pomogłam ;)
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Pattunia100
A) 4(3a+5)+3(5a-a) = 12a+20+15a-3a = 12a+20+12a = 24a+20
a) 4(3a+5)+3(5a-a)=12a+20+15a-3a=24a+20
b)2(7p-3)-5(3p-1)=14p-6-15p-1=-1p-7
c)-5(2-3m)-2m+8=-10+15m-2m+8=-2+13m
d)2x(3x-4)+x(5-2x)=6x^2-8x+5x-2x^2=4x^2-3x
e)3u(2-4u)-5u(u+3)=6u-12u^2-5u^2-15u=-9u-17u^2
f)-5t(2t-1)-2t(3-5t)=-10t^2+5t-6t+10t^2=-t
Mam nadzieję że pomogłam ;)
4(3a+5)+3(5a-a) =
12a+20+15a-3a =
12a+20+12a = 24a+20
b)
2(7p-3)- 5(3p-1) =
14p-6 -15p+1 = -p-5
c)
-5(2-3m)-2m+8 =
-19+15m-2m+8=
-8+13m = 13m-8
d)
2x(3x-4)+x(5-2x) =
6x²-8x+5x-2x² =
4x²-3x
e)
3u(2-4u)-5u(u+3) =
6u-12u²-5u²-15u =
-9u-17u²= -17u²-9u
f)
-5t (2t-1)-2t(3-5t) =
-10t²+6t-6t+10t²= 0