Question

Proszę, pomóżcie xx

x(32x-22y+45)-6x+7x^ =

(54x-30)-(11x-25)-(22x-9)=

(7x+2y)+(3x-8y)+(-2x-4)=

(l3a-2) X9-(5a+2)X10 =

x(32x-22y+45)-6x+7x^ =

Legenda:^ - do potęgi

X - mnożenie

Answer 1

x(32x-22y+45)-6x-7x²= 32x²-22xy+45x-6x-7x²=25x²-22xy+39x

(54x-30)-(11x-25)-(22x-9)= 54x-30-11x+25-22x+9=21x+4

(7x+2y)+(3x-8y)+(-2x-4)= 7x+2y+3x-8y-2x-4=8x-6y-4

(3a-2)×9-(5a+2)×10=27a-18(-5a-2)×10=27a-18-50a-20=-23a-38

Ostatnie jest takie samo jak pierwsze wiec rozwiązanie nie pisze.

 

Prosze o naj :)

Pozdrawiam ;p

Answer 2

x(32x-22y+45)-6x+7x^ = 32x^ -22xy + 45x - 6x + 7x^= 39 x^  + 39x -22xy

 

(54x-30)-(11x-25)-(22x-9)=54x-30-11x+25 -22x + 9= 21x  + 4

 

(7x+2y)+(3x-8y)+(-2x-4)=7x + 2y + 3x -8y - 2x -4= 8x - 6y -4

 

(l3a-2) * 9-(5a+2)* 10 = 117a - 18 - 50a - 20 = 67a - 38

 

x(32x-22y+45)-6x+7x^ =  32x^ - 22xy + 45x - 6x + 7x^=39x^  + 39 x - 22xy