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∡BAD = α = 180° - 150° = 30°
P - pole równoległoboku = IABI * IADI * sinα = 10 * 8 * 1/2 = 40
zad 2.29
a)
IABI = IBCI = ICDI = ADI = a = 6 - bok rombu
IDEI = h = 4 - wysokość rombu
P - pole = a * h = 6 * 4 = 24
b)
IABI = IBCI = ICDI = IADI = a = 5 - bok rombu
BD = d₁ = 8 - przekątna rombu
IADI² - (IBDI/2)² = (IACI/2)²
5² - 4² = (IACI/2)²
25 - 16 = (IACI/2)²
(IACI/2)² = 9
(IACI/2) = √9 = 3
IACI = 2 * 3 = 6
IACI = d₂
P - pole rombu = d₁d₂/2 = 8 * 6/2 = 48/2 = 24
c)
∡BAD = α = 60°
P - pole rombu = IABI * IADI * sin60° = 3 * 3 * √3/2 = 9√3/2 = 4,5√3