" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Ob=48cm
cosα=3/5
_____________________
Ostroslup ma 6 krawedzi, dlatego:
48:6=8[cm] → dlugosc krawedzi
cosα=3/5
cosα=|AS|/|AD|→|AS|/8
przyrownujemy:
|AS|/8=3/5
5|AS|=24
|AS|=24/5
Ztw. Pitagorasa:
|AS|²+|SD|²=|AD|²
|SD|=H
(24/5)²+H²=8²
H²=1600/25-576/25
H²=1024/25
H=32/5
P=Pp+Pb=a√3/4+3*a√3/4=64√3/4+3*64√3/4=64√3 [cm²]
V=1/3*Pp*H=1/3*a√3/4*H=1/3*64√3/4*32/5=512√3/15 [cm³]
...chyba ;)
2.
log₂(x+1)+log₂(x-1)=3
log₂(x+1)(x-1)=3
log₂(x²-1)=log₂8
x²-1=8
x²=9
x=3