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MgO + 2HNO3>Mg(NO3)2 + H2O
Mg(NO3)2 = 24+2*14+6*16=148g/mol
m =29,6
n=m/M=29,6/148=0,2 mola
1 mol MgO ------------1 mol Mg(NO3)2
x----------------------------0,2 mole
x=0,2 mole
MMgO=24+16=40g/mol
m=n*M=0,2*40=8 g MgO
4
2FeO + C>2Fe + Co2
MFeO=56+16=72g/mol
m=288
n=m/M=288/72=4
2mole FeO ------------2 mole Fe
4 mole FeO --------------x
x=4 mole Fe
MFe=56g/mol
m=n*M=4*56=224g Fe