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1.W 1500cm3 r-ru NaOH znajduje się 20g NaOH. Oblicz stężenie molowe tego roztworu.
M NaOH=40g/mol
40g NaOH ---- 1mol
20g NaOH ---- xmoli
x = 0,5mola
n=0,5mola
v=1,5dm3
Cm=n/v
Cm=0,5/1,5
Cm = 0,33mol/dm3
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M NaOH=40g/mol
40g NaOH ---- 1mol
20g NaOH ---- xmoli
x = 0,5mola
n=0,5mola
v=1,5dm3
Cm=n/v
Cm=0,5/1,5
Cm = 0,33mol/dm3