Proszę o szybką pomoc z zadaniem 9.4 DAJĘ NAJ (PIERWIASTKI)
a) 5\sqrt{8}= 5 \sqrt{2} * \sqrt{4}= 5*2 \sqrt{2} = 10 \sqrt{2}
b) 6 \sqrt{28}= 6 \sqrt{9} * \sqrt{3} = 6*3 \sqrt{3} = 18 \sqrt{3}
c)-3 \sqrt{44} = -3 \sqrt{4} * \sqrt{11} = -3*2 \sqrt{11} = -6 \sqrt{11}
d) -5 \sqrt{68}= -5 \sqrt{17} * \sqrt{4} = -5*2 \sqrt{17} = -10 \sqrt{17}
e)1/2 \sqrt{8}= 1/2 \sqrt{4}* \sqrt{2}= 1/2*2 \sqrt{2} = \sqrt{2}
f) 3/4 \sqrt{20} = 3/4 \sqrt{5} * \sqrt{4} = 3/4*2 \sqrt{5} = 6/4 \sqrt{5}
g) 5/6 \sqrt{48} = 5/6 \sqrt{16} * \sqrt{3} = 5/6*4 \sqrt{3} = 20/6 \sqrt{3}
h)3/8 \sqrt{72} = 3/8 \sqrt{9} * \sqrt{8}= 3/8*3 \sqrt{2} * \sqrt{4} = 9/8*2\sqrt{2} = 18/8 \sqrt{2}
i) 2/5 \sqrt{50} = 5/2 \sqrt{25*2} = 5/2*5 \sqrt{2}= 25/2 \sqrt{2}
j)\sqrt[3]{32}= \sqrt[3]{8*4}=2 \sqrt[3]{4}
k) \sqrt[3]{40}= \sqrt[3]{8*5}= 2\sqrt[3]{5}
l) \sqrt[3]{54}= \sqrt[3]{27*2}= 3\sqrt[3]{2}
ł) \sqrt[3]{135}= \sqrt[3]{27*5}=3 \sqrt[3]5}
m) \sqrt[3]{128}= \sqrt[3]{64*2}= 4\sqrt[3]{2}
n) \sqrt[3]{250}= \sqrt[3]{125*2}= 5\sqrt[3]{2}
o) \sqrt{300}= \sqrt{4*75} = 2 \sqrt{75} =2 \sqrt{25*3} = 2*5 \sqrt{3}= 10 \sqrt{3}
p) \sqrt[3]{108}= \sqrt[3]{27*4} = 3 \sqrt[3]{4}
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a) 5\sqrt{8}= 5 \sqrt{2} * \sqrt{4}= 5*2 \sqrt{2} = 10 \sqrt{2}
b) 6 \sqrt{28}= 6 \sqrt{9} * \sqrt{3} = 6*3 \sqrt{3} = 18 \sqrt{3}
c)-3 \sqrt{44} = -3 \sqrt{4} * \sqrt{11} = -3*2 \sqrt{11} = -6 \sqrt{11}
d) -5 \sqrt{68}= -5 \sqrt{17} * \sqrt{4} = -5*2 \sqrt{17} = -10 \sqrt{17}
e)1/2 \sqrt{8}= 1/2 \sqrt{4}* \sqrt{2}= 1/2*2 \sqrt{2} = \sqrt{2}
f) 3/4 \sqrt{20} = 3/4 \sqrt{5} * \sqrt{4} = 3/4*2 \sqrt{5} = 6/4 \sqrt{5}
g) 5/6 \sqrt{48} = 5/6 \sqrt{16} * \sqrt{3} = 5/6*4 \sqrt{3} = 20/6 \sqrt{3}
h)3/8 \sqrt{72} = 3/8 \sqrt{9} * \sqrt{8}= 3/8*3 \sqrt{2} * \sqrt{4} = 9/8*2\sqrt{2} = 18/8 \sqrt{2}
i) 2/5 \sqrt{50} = 5/2 \sqrt{25*2} = 5/2*5 \sqrt{2}= 25/2 \sqrt{2}
j)\sqrt[3]{32}= \sqrt[3]{8*4}=2 \sqrt[3]{4}
k) \sqrt[3]{40}= \sqrt[3]{8*5}= 2\sqrt[3]{5}
l) \sqrt[3]{54}= \sqrt[3]{27*2}= 3\sqrt[3]{2}
ł) \sqrt[3]{135}= \sqrt[3]{27*5}=3 \sqrt[3]5}
m) \sqrt[3]{128}= \sqrt[3]{64*2}= 4\sqrt[3]{2}
n) \sqrt[3]{250}= \sqrt[3]{125*2}= 5\sqrt[3]{2}
o) \sqrt{300}= \sqrt{4*75} = 2 \sqrt{75} =2 \sqrt{25*3} = 2*5 \sqrt{3}= 10 \sqrt{3}
p) \sqrt[3]{108}= \sqrt[3]{27*4} = 3 \sqrt[3]{4}
a) 5\sqrt{8}= 5 \sqrt{2} * \sqrt{4}= 5*2 \sqrt{2} = 10 \sqrt{2}
b) 6 \sqrt{28}= 6 \sqrt{9} * \sqrt{3} = 6*3 \sqrt{3} = 18 \sqrt{3}
c)-3 \sqrt{44} = -3 \sqrt{4} * \sqrt{11} = -3*2 \sqrt{11} = -6 \sqrt{11}
d) -5 \sqrt{68}= -5 \sqrt{17} * \sqrt{4} = -5*2 \sqrt{17} = -10 \sqrt{17}
e)1/2 \sqrt{8}= 1/2 \sqrt{4}* \sqrt{2}= 1/2*2 \sqrt{2} = \sqrt{2}
f) 3/4 \sqrt{20} = 3/4 \sqrt{5} * \sqrt{4} = 3/4*2 \sqrt{5} = 6/4 \sqrt{5}
g) 5/6 \sqrt{48} = 5/6 \sqrt{16} * \sqrt{3} = 5/6*4 \sqrt{3} = 20/6 \sqrt{3}
h)3/8 \sqrt{72} = 3/8 \sqrt{9} * \sqrt{8}= 3/8*3 \sqrt{2} * \sqrt{4} = 9/8*2\sqrt{2} = 18/8 \sqrt{2}
i) 2/5 \sqrt{50} = 5/2 \sqrt{25*2} = 5/2*5 \sqrt{2}= 25/2 \sqrt{2}
j)\sqrt[3]{32}= \sqrt[3]{8*4}=2 \sqrt[3]{4}
k) \sqrt[3]{40}= \sqrt[3]{8*5}= 2\sqrt[3]{5}
l) \sqrt[3]{54}= \sqrt[3]{27*2}= 3\sqrt[3]{2}
ł) \sqrt[3]{135}= \sqrt[3]{27*5}=3 \sqrt[3]5}
m) \sqrt[3]{128}= \sqrt[3]{64*2}= 4\sqrt[3]{2}
n) \sqrt[3]{250}= \sqrt[3]{125*2}= 5\sqrt[3]{2}
o) \sqrt{300}= \sqrt{4*75} = 2 \sqrt{75} =2 \sqrt{25*3} = 2*5 \sqrt{3}= 10 \sqrt{3}
p) \sqrt[3]{108}= \sqrt[3]{27*4} = 3 \sqrt[3]{4}