Proszę o szybką pomoc. Prosze rozwiązać równanie:
x^2=(1-x)(1+x)
x² = 1 - x²
2x² - 1 = 0
Δ = 0² - 4*2*(-1) = 8
x₁ = (0+ √8) / 4 = (2√2) / 4 = (√2) / 2.
x₂ = (0 - √8) / 4 = (-2√2) / 4 = (-√2) / 2.
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x² = 1 - x²
2x² - 1 = 0
Δ = 0² - 4*2*(-1) = 8
x₁ = (0+ √8) / 4 = (2√2) / 4 = (√2) / 2.
x₂ = (0 - √8) / 4 = (-2√2) / 4 = (-√2) / 2.