[tex]a)(-2)^{5} > 3^{-3} > 15^{0} > 2^{3} > 3^{2}\\2^{3}=8\\3^{-3}=\frac{1}{27}\\15^{0}=1\\(-2)^{5}=-32\\3^{2}=9\\\\[/tex]
[tex]b)(-5)^{3} > (\frac{1}{3})^{3} > (1\frac{1}{2})^{-2} > (\frac{2}{3})^{-2} > (\frac{1}{15})^{-1}\\(\frac{1}{3})^{3}=\frac{1}{27}=\frac{4}{108}\\(\frac{1}{15})^{-1}=15\\(\frac{2}{3})^{-2}=(\frac{3}{2})^{2}=\frac{9}{4}=\frac{243}{108}\\(-5)^{3}=-125\\(1\frac{1}{2})^{-2}=(\frac{3}{2})^{-2}=(\frac{2}{3})^{2}=\frac{4}{9}=\frac{48}{108}[/tex]
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[tex]a)(-2)^{5} > 3^{-3} > 15^{0} > 2^{3} > 3^{2}\\2^{3}=8\\3^{-3}=\frac{1}{27}\\15^{0}=1\\(-2)^{5}=-32\\3^{2}=9\\\\[/tex]
[tex]b)(-5)^{3} > (\frac{1}{3})^{3} > (1\frac{1}{2})^{-2} > (\frac{2}{3})^{-2} > (\frac{1}{15})^{-1}\\(\frac{1}{3})^{3}=\frac{1}{27}=\frac{4}{108}\\(\frac{1}{15})^{-1}=15\\(\frac{2}{3})^{-2}=(\frac{3}{2})^{2}=\frac{9}{4}=\frac{243}{108}\\(-5)^{3}=-125\\(1\frac{1}{2})^{-2}=(\frac{3}{2})^{-2}=(\frac{2}{3})^{2}=\frac{4}{9}=\frac{48}{108}[/tex]