proszę o rozwiązanie zadania 2 z matematyki oblicz wartości wielomianu tylko zadanie 2 , zdjęcie w załączniku
a)
w(0)=3*0^3+0^2-2*0-3= -3
w(1)= -1
w(-2)= -19
w(-3)= -69
b)
w(0)= 2
w(1)= -4
w(-2)= 32
w(-3)= 80
c)
w(0)= -4
w(-2)= -11
w(-3)= -82
d)
w(0)= -10
w(1)= -10
w(-2)= -58
w(-3)= -214
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a)
w(0)=3*0^3+0^2-2*0-3= -3
w(1)= -1
w(-2)= -19
w(-3)= -69
b)
w(0)= 2
w(1)= -4
w(-2)= 32
w(-3)= 80
c)
w(0)= -4
w(1)= -4
w(-2)= -11
w(-3)= -82
d)
w(0)= -10
w(1)= -10
w(-2)= -58
w(-3)= -214