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x^3+3x^2+2x=-2/3x^2
x=-3
-3^3+3*(-3)^2+2*(-3)=-2/3*(-3)^2
-27+27-6=-2/3*9
-6=-2*3
-6=-6 L=P Prawda.
Zada 2
(4x-3)^2-3(x+2)(x-2)-(4x+2)^2=16x^2-24x+9-3x^2+12-16x^2-16x-4=
16x^2-16x^2-3x^2-24x-16x+9+12-4= -3x^2-40x+17
Tam jest napisane? x=- +2 ? czy x=- +2 pod pierwiastkiem?
Zad 3
x^3+2x^2+ax+15 dla x=-3
x^3+2x^2+ax+15=3
(-3)^3+2(-3)^2-3a+15=3
-27+18-3a+15=3
3=3a
a=1