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a boki kwadrata
d = a+2 przekantna
2a² = d²
d = a√2
a+2 = a√2
2 = a(√2 - 1)
a = 2/(√2 - 1) = 2(√2 + 1)/[(√2 + 1)(√2 - 1)] = 2(√2 + 1)/(2-1)=2(√2 + 1)
a = 2(√2 + 1)
O = 4a = 8(√2 + 1) obwod
5.
P = 24 pole
h = a/2 wysokosc (a - dluzsa podstawa)
b = 4 krotsza podstawa
c - ? dlugosc ramieia
P = (a+b)h/2 = (a+4)a/4
24 = (a+4)a/4
96 = a² + 4a
a² + 4a - 96 = 0
D = 400
a = (-4+20)/2 = 8
h = a/2 = 8/2 = 4
c = √(2²+4²) = √20 = 2√5 dlugosc ramieia
6.
12(12 - 3)/2 = 108/2 = 54