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log(2,(x³+16))>log(2,(x²+x))
lg(x³+16)/lg2 > lg(x²+x)/lg2
lg(x³+16) > lg(x²+x)
x³+16 > 0
x > -∛16
x > -2∛2
x ∈ (-2∛2; ∞)
x^2+x > 0 => x ∈ (-∞; ∞)
odp. x ∈ (-2∛2; ∞)
i)
log²(x)<9
x > 0
logx < 3
x < 10^3
x < 1000
logx >- 3
x > 10^-3
x > 0,001
odp. x ∈ (0,001; 1000)
Dziedzina: x>0