Proszę o rozwiązanie 2|x-4|+|3x-12|<=4+|8-2x|
2 Ix-4I + I3x-12I ≤ 4 + I8-2xI
2 Ix-4I +3 Ix-4I ≤ 4 + I -2(x-4)I
5 Ix-4I ≤ 4 + 2 Ix-4I
5 Ix-4I -2 Ix-4I ≤ 4
3 Ix-4I ≤ 4 /:3
Ix-4I ≤ 4/3
- 4/3 ≤ x-4 ≤ 4/3
- 4/3 +4 ≤ x ≤ 4/3 + 4
2⅔ ≤ x ≤ 5⅓
Odp. x∈ < 2⅔, 5⅓ >
2|x-4|+3|x-4|<=4+2|x-4|
3|x-4|<=4
f(x)=3|x-4|-4 i fx<=0
patrz zalacznik
x∈[2i2/3 ; 5i1/3]
wykresy polecam
http://l5.pk.edu.pl/~kraus/bryly_3d/fun_yx.php
pozdr
Hans
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2 Ix-4I + I3x-12I ≤ 4 + I8-2xI
2 Ix-4I +3 Ix-4I ≤ 4 + I -2(x-4)I
5 Ix-4I ≤ 4 + 2 Ix-4I
5 Ix-4I -2 Ix-4I ≤ 4
3 Ix-4I ≤ 4 /:3
Ix-4I ≤ 4/3
- 4/3 ≤ x-4 ≤ 4/3
- 4/3 +4 ≤ x ≤ 4/3 + 4
2⅔ ≤ x ≤ 5⅓
Odp. x∈ < 2⅔, 5⅓ >
2|x-4|+3|x-4|<=4+2|x-4|
3|x-4|<=4
f(x)=3|x-4|-4 i fx<=0
patrz zalacznik
x∈[2i2/3 ; 5i1/3]
wykresy polecam
http://l5.pk.edu.pl/~kraus/bryly_3d/fun_yx.php
pozdr
Hans