Odpowiedź:
[tex]3,\\f(x)=-x^2+3x+29\\x=-4\\f(-4)=(-4)^2+3*(-4)+29\\f(-4)=16-12+29\\f(-4)=33\\\\4,\\f(-4)==x^2+2x+2\\w(p,q)\\p=\frac{-2}{2}=-1\\ f(-1)=(-1)^2+2*(-1)+2\\f(-1)=1-2+2\\f(-1)=1\\W(-1,1)[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]3,\\f(x)=-x^2+3x+29\\x=-4\\f(-4)=(-4)^2+3*(-4)+29\\f(-4)=16-12+29\\f(-4)=33\\\\4,\\f(-4)==x^2+2x+2\\w(p,q)\\p=\frac{-2}{2}=-1\\ f(-1)=(-1)^2+2*(-1)+2\\f(-1)=1-2+2\\f(-1)=1\\W(-1,1)[/tex]
Szczegółowe wyjaśnienie: