Proszę o pomoc.Pilne !
Oblicz przykłady logarytmów :
a) log podstawa 0,2 z 250-log podstawa 0,2 z 2 =
b) log podst. 3 z 2 -log podst.3 z 30 +log podst 3 z 5=
c) Log podst.9 z 54 -log podst.9 z 2+ log 100=
d) log podst 3 z 2+log podst 3 z 27 - log 36=
e)log podst 3 z 9∛+ log podst ⅕ 25 pierwiastek z 5=
f) log podst 9 z 0,(6) -log podst 9 z 2 +log podst 5 z 1=
Daję najlepszą odp !
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
log 1/5 [ 250 ] - log 1/5 [ 2] = log 1/5 [ 250/2] = log 1/5 [ 125 ] = - 3 ,
bo (1/5)^( -3) = 5^3 = 125
b)
log 3 [2] - log 3 [ 30] + log 3 [ 5] = log 3 [ 2 *5] - log 3 [ 30] =
= log3 [ 10] - log 3 [ 30] = log 3 [ 10/30] = log 3 [ 1/3] = - 1,
bo 3^(-1) = 1/3
c)
log 9 [ 54] - log 9 [ 2] + log 100 = log 9 [54/2] + 2 = log 9[ 27] + 2 =
= (1/2) log 3 [27] + 2 = (1/2) *3 + 2 = 1,5 + 2 = 3,5
d)
log 3 [ 2] + log 3 [27] - log 3[ 6 ] = log 3 [ 2*27] - log 3[ 6 ]= log 3 [ 54/6] =
= log 3 [9 ] = 2
e)
f)
log 9 [ 0,(6) ] - log 9 [ 2] + log 5 [ 1] = log 9 [ 2/3 ] - log 9 [ 2] + 0 =
= log 9 [ ( 2/3) : 2] = log 9 [ 1/3] = - 1/2
================================