Question

proszę o pomoc w tym zadaniu ​

Answer 1

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Answer 2

Zadanie 15

[tex]a) \frac{3}{7}*28=3*4=12\\ b)\frac{1}{3}*3\frac{3}{4} =\frac{1}{3}*\frac{15}{4}=\frac{5}{4}=1\frac{1}{4} \\c)1 \frac{1}{7}*2\frac{1}{4}=\frac{8}{7}*\frac{9}{4}=\frac{18}{7} =2\frac{4}{7}[/tex]

Zadanie 16

[tex]a) 1\frac{3}{4} *1\frac{1}{7} -3:4\frac{1}{2} = \frac{7}{4} * \frac{8}{7} -3: \frac{9}{2}=2 -3*\frac{2}{9}=2-\frac{2}{3} =1\frac{1}{3}[/tex]

[tex]b) 1\frac{5}{7}*(2\frac{3}{4} -1\frac{2}{3}:4) =\frac{12}{7}*(\frac{11}{4}-\frac{5}{3}*\frac{1}{4})= \frac{12}{7}*(\frac{11}{4} -\frac{5}{12})= \frac{12}{7}*(\frac{33}{12} -\frac{5}{12})=\frac{12}{7}*\frac{28}{12} =4[/tex]

[tex]c) 3\frac{1}{3}*(2\frac{1}{4} -1\frac{1}{2}:5) =\frac{10}{3}*(\frac{9}{4}-\frac{3}{2}*\frac{1}{5})= \frac{10}{3}*(\frac{9}{4} -\frac{3}{10})= \frac{10}{3}*(\frac{90}{40} -\frac{12}{40})=\frac{10}{3}*\frac{78}{40} =\frac{26}{4}=6\frac{2}{4} =6\frac{1}{2}[/tex]

[tex]d) \frac{3\frac{1}{4}+\frac{1}{2} }{3\frac{1}{3}*(1\frac{5}{6}-1\frac{1}{12}) } =\frac{\frac{13}{4}+\frac{2}{4} } {\frac{10}{3} *(\frac{11}{6} -\frac{13}{12}) } =\frac{\frac{15}{4} }{\frac{10}{3}*(\frac{22}{12} -\frac{13}{12})} = \frac{\frac{15}{4} }{\frac{10}{3}*\frac{9}{12} } = \frac{\frac{15}{4} }{\frac{15}{6}}=\frac{15}{4} *\frac{6}{15}=\frac{3}{2}=1\frac{1}{2}[/tex]