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62u - X
X = (62u*100%) : 262u = 23,66%
Odp : 23,66%
masa Mg₃(PO₄)₂: 3 * 24u + 2 * (31u + 4 * 16u) = 262u
masa fosforu w Mg₃(PO₄)₂: 2 * 31u = 62u
262u ---- 100%
62u ---- x %
x = (62u * 100%) : 262u ≈ 23,66%